NCERT Solutions for class 10 Maths chapter 7: Coordinate Geometry

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The NCERT solutions for class 10 maths chapter 7 Coordinate Geometry are provided in the article to help students prepare for their class 10 maths board exam. Coordinate Geometry is a branch of geometry that helps in determining the position of points in a plane with the help of ordered pair of numbers called coordinates.

Chapter 7 Coordinate Geometry is a part of Unit 3 Coordinate Geometry as per the class 10 syllabus 2022-23. This chapter carries a weightage of 06 marks in cbse class 10 maths board exam. The important topics from this chapter includes distance formula, section formula and area of a triangle. 

Download: NCERT Solutions for Class 10 Maths Chapter 7 pdf


NCERT Solutions for Class 10 Maths Chapter 7

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Class 10 Maths Chapter 7 Coordinate Geometry: Important Topics

The important topics of chapter 7 coodinate geometry are given below:

  • Distance Formula – In coordinate geometry, distance formula is used to find the distance between two points in a coordinate plane. It is derived with the help of Pythagoras theorem.

Distance formula, for two points say P and Q with coordinates (x1,y1) and (x2,y2) respectively, is given by;

\(PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)

  • Section Formula – Section formula is used to find the coordinates of the point that divides a line segment into two ratios.

Section formula, for a point P dividing a line segment AB with A (x1,y1) and B (x2,y2) in the ratio m1:m2 , is given by;

\(P(x,y) = (\frac{m_1x_2 + m_2x_1}{m_1 + m_2} , \frac{m_1y_2 + m_2y_1}{m_1 + m_2})\)

  • Area of a Triangle – Area of a Triangle can be calculated when coordinates of the vertices of the triangle are given.

The formula for calculating area of a triangle ABC with vertices A (x1,y1), B (x2,y2) and C (x3,y3) is given by;

\(Area = \frac{1}{2} [x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)]\)


NCERT Solutions for Class 10 Maths Chapter 7 Exercises:

The NCERTsolutions of all the exercises of class 10 maths chapter 7 Coordinate Geometry are given below:


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Study Materials for Class 10 Maths:

CBSE X Related Questions

  • 1.
    If for a data, median is 5 and mode is 4, then mean is equal to :

      • 7
      • 11
      • \(\frac{11}{2}\)
      • \(\frac{14}{3}\)

    • 2.
      In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

        • $6$
        • $4$
        • $\pm 4$
        • $3$

      • 3.
        If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

          • \(\frac{7}{2}\)
          • \(\frac{6}{7}\)
          • \(\frac{-7}{6}\)
          • \(\frac{7}{6}\)

        • 4.
          Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
          Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

            • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
            • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
            • Assertion (A) is true, but Reason (R) is false.
            • Assertion (A) is false, but Reason (R) is true.

          • 5.
            If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

              • \(4 \text{ cm}\)
              • \(4\sqrt{2} \text{ cm}\)
              • \(8 \text{ cm}\)
              • \(2\sqrt{2} \text{ cm}\)

            • 6.
              The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

                • \((x + 2), (x - 5)\)
                • \((x + 5), (x - 2)\)
                • \((x + 1), (x - 5)\)
                • \((x - 1), (x + 2)\)

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